Termination w.r.t. Q of the following Term Rewriting System could not be shown:

Q restricted rewrite system:
The TRS R consists of the following rules:

f1(X) -> if3(X, c, f1(true))
if3(true, X, Y) -> X
if3(false, X, Y) -> Y

Q is empty.


QTRS
  ↳ Non-Overlap Check

Q restricted rewrite system:
The TRS R consists of the following rules:

f1(X) -> if3(X, c, f1(true))
if3(true, X, Y) -> X
if3(false, X, Y) -> Y

Q is empty.

The TRS is non-overlapping. Hence, we can switch to innermost.

↳ QTRS
  ↳ Non-Overlap Check
QTRS
      ↳ DependencyPairsProof

Q restricted rewrite system:
The TRS R consists of the following rules:

f1(X) -> if3(X, c, f1(true))
if3(true, X, Y) -> X
if3(false, X, Y) -> Y

The set Q consists of the following terms:

f1(x0)
if3(true, x0, x1)
if3(false, x0, x1)


Q DP problem:
The TRS P consists of the following rules:

F1(X) -> F1(true)
F1(X) -> IF3(X, c, f1(true))

The TRS R consists of the following rules:

f1(X) -> if3(X, c, f1(true))
if3(true, X, Y) -> X
if3(false, X, Y) -> Y

The set Q consists of the following terms:

f1(x0)
if3(true, x0, x1)
if3(false, x0, x1)

We have to consider all minimal (P,Q,R)-chains.

↳ QTRS
  ↳ Non-Overlap Check
    ↳ QTRS
      ↳ DependencyPairsProof
QDP
          ↳ DependencyGraphProof

Q DP problem:
The TRS P consists of the following rules:

F1(X) -> F1(true)
F1(X) -> IF3(X, c, f1(true))

The TRS R consists of the following rules:

f1(X) -> if3(X, c, f1(true))
if3(true, X, Y) -> X
if3(false, X, Y) -> Y

The set Q consists of the following terms:

f1(x0)
if3(true, x0, x1)
if3(false, x0, x1)

We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph contains 1 SCC with 1 less node.

↳ QTRS
  ↳ Non-Overlap Check
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof
QDP

Q DP problem:
The TRS P consists of the following rules:

F1(X) -> F1(true)

The TRS R consists of the following rules:

f1(X) -> if3(X, c, f1(true))
if3(true, X, Y) -> X
if3(false, X, Y) -> Y

The set Q consists of the following terms:

f1(x0)
if3(true, x0, x1)
if3(false, x0, x1)

We have to consider all minimal (P,Q,R)-chains.